2018-2022英语周报高二14答案

短文改错Our school is locating at the centre of Beijing, that is one of the largest schools in the city with about 200ocateachers and over 2,000 students. Our subject include Chinese, English, maths, physics, history and so on.Most of us paid great attention to the study of English, Chinese and maths because we are very important in theuniversity entrance exam. We take specially interest in English. Although we have spent much time on it,butre still find it's difficult A learn the language well. In the afternoonstayingschool fout one hour to take exercise before leaving at home

24.解析:(1)设C与A碰撞前的速度大小为v,由动能定理ponegs-bmeufm解得:=6m/s。(2)设C与A碰撞后粘在一起的速度为v2,由动量守恒定律Incu1=(ma nc)解得:=3m/sA在运动过程中,小球B保持静止,该过程时间为h,设A与B磁撞前的速度为v,由动能定理和动量定理u(ma me)go=6(mA mc )v-d(ma mc)vu(mA ms mc)gt:=(ma mc)v-(ma me)v解得:=1m/s、1=0.5s,设A第一次与B碰撞后A和B的速度分别为v和,由动量守恒定律和机械能守恒定律:(ma nc)v=(a mc)v4 mgUs(ma me)v=6(mA mc)v amans解得:v=0,v=1m/s,B运动过程中A保持静止。设经过时间t2,B第二次与A碰撞:L第二次碰撞后A与B的速度分别为v和w,由动量守恒定律和机械能守恒定律mBUS=(mA me)u ms vi,2m=2(m m) 2m,解得:w=1m/s,w=0,A运动中B保持静止,设A滑动距离为x、时间为t,由动能定理和动量定理以(m4 m3 m)gx=0-1(m4 m)t,u(mA mg mc)gt3=0-(na mc)v-u(mA B nc)gt3=0-(nA mc)vs解得:x=0.125m

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