参考答案B说明分析设P(t,s),Q(t,-s),t∈[0,a],s∈[0,b],A(-a,0),B(a,0),k, 1 k, 1(2当且仅当5=-5,即t=0时等号成立t aA,B是椭圆x2=1(“b>0)长轴的两个端点,P,Q是椭圆上关于x轴对称的两点,P(t,s),Q(t,=s,即当s=b时,k k的值最小, k的最小值为椭圆的离心率为≌2:c=√21,得a=√2b,∷ k的最小值为√2.故选B
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