12.答案(1)3.60(1分2)物北吧)地面成挡光片)的高度B1分)(M=m)1=21(m ()2分)(3)(2分(2分)命题透析本题考查验证机械能守恒定律,考查考生的实验能力,考查科学探究。思路点拨(1)该游标卡尺为20分度,最小精确度为0.05mm,游标卡尺读数为3mm 12×0.05mm=3.60mm;(2)物块A刚要落地时的速度=,,设物块A下落的高度H,则(M-m)gH=(m M)t2,即(M-m)gh2(m M)(//,还需要测量的是重物A(或光电门)开始时离地面(或挡光片)的高度H(3)由(M-m)6∥=、1(m M)得到M2m mgh当此图线与纵轴的截距为,斜率为4m,则机械能守恒定律得到验证。
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