13.(1)BC(2分)(2)2.00(2分)(3)C(2分)【解析】(1)本题轻绳中的拉力可以由力传感器测出,不需要用天平測出砂和砂桶的总质量,也就不需要使砂和砂桶的总质量m远小于小车的质量M,A、D项错误;实验时需将长木板右端垫高,以平衡摩擦力,B项正确;实验时,小车应靠近打点计时器,先接通电源,再释放小车,需记录力传感器的示数,C项正确(2)相邻计数点间的时间间隔为T=5×0.02s0.1s,根据△x=a7,运用逐差法得9T7.10 9.13 11.09-5.12-3.09-1.10×10-2m/s2≈9×0.012.00m/s2(3)由牛顿第二定律得2F=(M m。)a,则有aM mF,F图象的斜率k=22M m。小车的质量为M=k-m,故C项正确
【参考范文】Dear Michaem writing to tell you about the classical Chinese poetry festival to be held in our school at this weekendme famous poets as well as how to read and write classical Chinese poems, and poetry readings, which willhelp you to develop an appreciation of classical Chinese poetry. Besides, there is a poetry writing contest, andwhoever is interestedoem writing can take partSo why not come to the festival? I'm sure you will learn a lot as a lover of classical Chinese poetry.Looking forward to your replyLi Hua
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