【语篇类型】一记叙文【主题语境】人与自我一助人经历【文章大意】本文讲述了作者在芝加哥偶遇一个无家可归的人并施以援手的故事。【核心素养】语篇以作者帮助一个无家可归的人为背景,展示了人性的闪光点和生活中的真善美,助力考生树立正确的价值观,体现了文化意识这一核心素养。郾熟词新义1.dow常用义:淋浴文章义:大量给予He showered her with gifts.他送给她许多礼物。2. finance常用义:n.资金;财政,金融,财务文章义:t.为……提供资金The concerts are financed by the Arts Council.音乐会由艺术协会出资举办词汇积累 flash back(osh.)回忆,回想,回顾;(尤指电影、书等)闪回,倒叙Her thoughts flashed back to their wedding day.她回忆起他们婚礼那一天的情景。难句分析1 only had a few dollars left in my wallet,,. but I went tobu连接两个并列句him directly, bent down and handed them to this fellow, talking withhim, touching his hand and wishing him well before I left现在分词短语作伴随状语before引导时间状语从句译文:我的钱包里只剩下几美元了,但在我离开前,我径直走到他面前,弯下腰,把钱递給他,并和他交谈,抚摸他的手,祝他一切顺利。4.D【关键能力】考查理解具体信息的能力。【解题思路】根据第二段的" a man sitting on the sidewalk..Mymind flashed back and I realized I had seen a homeless person oncebefore:Me"可知,作者在外出散步时看到了一个无家可归的人,这使他想起了自己无家可归的经历。5.c【关键能力】考查推理判断的能力。【解题思路】根据第三段的" the home I grew up in caught fire in themiddle of the night. I can still remember the fire destroyed everythingwe owned ""our small town communitytemporary house"可知,作者的家遭遇火灾,大火烧毁了他们的一切使他们无家可归。第二段的" I had seen a homeless person oncebefore:Me"也是提示。6.D【关键能力】考查理解具体信息的能力。【解题思路】根据第四段的" I only had a few dollars left in mywallet, but I went to him directly, bent down and handed them to thisfellow, talking with him, touching his hand and wishing him well beforeI left"可知,作者把身上仅有的几美元都给了那个无家可归的人,且和他交谈,安慰了他。7A【关键能力】考查推理判断的能力。【解题思路】根据最后一段的内容可知,作者一直并且将继续帮助他人,作者认为即使自己所能做的非常有限,但只要人人付出点,世界就会变得更好。结合上文中的“ Thankfully, our small towncommunity showered us with love and care""I could remember feelingloved even after losing so much"可推知,作者感恩于自己得到的爱与关怀,也希望将其传递下去故选A项”关爱使世界更美好”。B项”人之初性本善";C项"不尝试,不知晓”;D项"凡事要肯等待"。
20.解(1)因为c=2,所以a=①,(1分)依题意A(-a,0),M(-a,b),F(-c,0),所以△AMF的面积S2(a-c)b=即(a-c)2b2=(2-1)②,(2分)又b2=a2-c2③,(3分)解①②③得a=2,b=c=1,(4分)所以椭圆C的方程为x y2=1.(5分)(2)依题意,直线l的斜率存在且不为0,设其方程为y=k(x 2),代入 y2=1,消去y,得(1 2k2)x2 42k2x 4k2-2=0,(6分)因为A(-,0),可设P(x,),则(-互)x,=4=2,得x=2=2E2,(7分)因为⊥l,且过点B(,0),故可设直线l方程为yA(x-),与y=k(x 2)联立解得Q点的横坐标为x0=2-2k1 k2-(8分)由S1=2S2可得AP|=2|PQ1,所以AP=2PQ,(9分)则xp =2(x-x),即3x=2x0-2,(10分)所以3×2-22E=2×2-2E-,即3=6=1=31 22-1 k2,(11分)化简得k2=1,所以k=±1所以直线l的斜率k=1或-1.(12分)
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