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3.C〖解析】A.已知亚磷酸(HPO3)是一种二元弱酸,故I3PO3与足量的NaOH溶液反应生成Na2HPO3,不能生成 Na3 PO,A错误;B.弱酸的电离过程是一个吸热过程,升高温度促进弱酸的电离平衡正向移动,故对亚磷酸溶液升温,溶液中α(H)増大,溶液的pH值变小,B错误;C.向亚磷酸溶液中加入少量NaOH固体电离平衡正向移动,溶液中c(H )减小,则(HPO)_Kc(H3PO)c(Ⅳ增大,C正确;D.对0.01mol/L的H3PO3溶液加水稀释,溶液中∏、∏PO3、IPOξ离子浓度均减小,但根据水的离子积可知,温度不变时Kc(H)c(OH)是一个常数,故c(OH)增大,D错误;答案选C
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