2021-2022 英语周报 高二 FJM 31答案

【语篇类型】一记叙文【主题语境】人与自我一助人经历【文章大意】本文讲述了作者在芝加哥偶遇一个无家可归的人并施以援手的故事。【核心素养】语篇以作者帮助一个无家可归的人为背景,展示了人性的闪光点和生活中的真善美,助力考生树立正确的价值观,体现了文化意识这一核心素养。郾熟词新义1.dow常用义:淋浴文章义:大量给予He showered her with gifts.他送给她许多礼物。2. finance常用义:n.资金;财政,金融,财务文章义:t.为……提供资金The concerts are financed by the Arts Council.音乐会由艺术协会出资举办词汇积累 flash back(osh.)回忆,回想,回顾;(尤指电影、书等)闪回,倒叙Her thoughts flashed back to their wedding day.她回忆起他们婚礼那一天的情景。难句分析1 only had a few dollars left in my wallet,,. but I went tobu连接两个并列句him directly, bent down and handed them to this fellow, talking withhim, touching his hand and wishing him well before I left现在分词短语作伴随状语before引导时间状语从句译文:我的钱包里只剩下几美元了,但在我离开前,我径直走到他面前,弯下腰,把钱递給他,并和他交谈,抚摸他的手,祝他一切顺利。4.D【关键能力】考查理解具体信息的能力。【解题思路】根据第二段的" a man sitting on the sidewalk..Mymind flashed back and I realized I had seen a homeless person oncebefore:Me"可知,作者在外出散步时看到了一个无家可归的人,这使他想起了自己无家可归的经历。5.c【关键能力】考查推理判断的能力。【解题思路】根据第三段的" the home I grew up in caught fire in themiddle of the night. I can still remember the fire destroyed everythingwe owned ""our small town communitytemporary house"可知,作者的家遭遇火灾,大火烧毁了他们的一切使他们无家可归。第二段的" I had seen a homeless person oncebefore:Me"也是提示。6.D【关键能力】考查理解具体信息的能力。【解题思路】根据第四段的" I only had a few dollars left in mywallet, but I went to him directly, bent down and handed them to thisfellow, talking with him, touching his hand and wishing him well beforeI left"可知,作者把身上仅有的几美元都给了那个无家可归的人,且和他交谈,安慰了他。7A【关键能力】考查推理判断的能力。【解题思路】根据最后一段的内容可知,作者一直并且将继续帮助他人,作者认为即使自己所能做的非常有限,但只要人人付出点,世界就会变得更好。结合上文中的“ Thankfully, our small towncommunity showered us with love and care""I could remember feelingloved even after losing so much"可推知,作者感恩于自己得到的爱与关怀,也希望将其传递下去故选A项”关爱使世界更美好”。B项”人之初性本善";C项"不尝试,不知晓”;D项"凡事要肯等待"。

20.(本小题满分12分)解:(1)设P(x,y),A(x,0),B(0,y),由Op=OH √2OB,得(x,y)=(x,0) √2(0,y),xX=o,即得2因为AB=√6,所以x y2=6,将(x,y)代入x2 y2=6,整理得点P的轨迹C的方程为y x=126(2)设M(x,y),N(x2,y2),假设存在这样的点S(O,1)满足∠RSM ∠RSN=兀,文科数学参考答案·第5页(共9页)当直线l的斜率存在时,设为y=kx 6,代入椭圆 =1中,126得(k2 2)x2 12kx 24=0,△=144k2-96(k2 2)=48(k2-4)>012k24x1 x2k2 2k2 2∵∠RSM ∠RSN=兀,∴k1s ks=0,⌒×々y即x2(V1-1) x1(y2-D)=x2(k 6-1) x(kx2 6-1=2kx2 (6-1)x x2)=2h2412k12k (6(t-2)=0.k2 2k2 2k2 2k≠0,∴t=2,即S(O,2)当斜率不存在时,直线l也过(0,2)综上,y轴上存在定点S(0,2),使得∠RSM ∠RSN=兀总成立

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