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6.(15分)(1)保护氨基(1分)取代反应(1分)硝基、羟基分)NIcoleO, NCH, BINHCOCH3HBr(2分)N(CH2 CH CINCH(2分)C16H2 N, CI(2分(5)6(2分)H -N-N-CH-CH2-CH:CH3-CHCH-CH3(2分)CH3【解析】本题主要考查了官能团判断、化学方程式的书写、结构简式判断、反应类型判断、同分异构体的书写等知识点(1)在物质E中生成了氨基并参与后续反应,所以A转化为B的目的是保护氨基。根据已知信息②可知,生成D的反应类型为取代反应。E中含氧官能团的名称为硝基、羟基。(2)B生成C的化学方程式为NHCOCH3BCHo BrNHCOCH HBr.O, N(3)根据E、F的结构可判断,试剂X的结构简式(CHCH- CI)2为C1C1(4)根据已知信息③和F、H的结构可得G的结构简式为NCH中间体H的分子式为C6H2NPO4C(5)根据题意,相当于在异戊烷和新戊烷上加入N一N原子团,符合条件的共有6种,其中,含有手性碳原子的化合物的结构简式为CH3-N= N-CH-Ch2=CH3、CH3NHCH -CH-CH-CHCH
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