9解:(1)∵f(x)=e-(1),∴f(x)=e ∴f(x)>0对任意x∈R都成立,∵·f(x)在R上是增函数又∵f(x)的定义域为R,且f(-x)=e-e=-f(x)f(x)是奇函数(8分)(2)存在.由(1)知f(x)在R上是增函数和奇函数,则f(x-1) f(x2-P2)≥0对一切x∈R都成立,(10分台f(x2-P2)≥f(t-x)对一切x∈R都成立,台x2-2≥-x对一切x∈R都成立,e2 ≤x2 x=(x 对一切x∈R都成立2 长≤(x2 x)m42 t 1(x )≤0(16分)又( 号)≥0(x 号)存在t=-1,使不等式f(x-1) f(x2-2)≥o对一切x∈R都成立(20分)
写作Dear TonyYou say you have dimeulty adap ting to the new study and life herelow exactly how you feel.(表示关心) You must be very anxious,butqui te normal since this is your first time to study in a foreig【高分句型-】 Just relax. First, break bearning goaIs into small stepsen get involved in school activities, wherou can make more friends.【高分句型二】(帮他分析原因Hopefully my sugsestions would be helpfum always the person youcan count on提供建议)s t
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