One possible version:My mom also joined the conversation. " Anahy, I have also noticed that you never pay attention to us, yourbrother or sister. It seems that you have your own little world now and we dont communicate as much as beforebecause of your phone. "I acted as if they were wrong, but then I started to wonder if it was true that I wasbeing impolite.A week later I tried going a whole day without a cell phone and it didn t go that badly. My relativescame over and it was the first time that I wasn't using my phone since I had one. Everyone noticed because theywere asking me about it. It got really annoying because everyone shouted"Wow! Finally you are not using yourphone! "That day I had so much fun because I was actually spending time with my family and paying attention tothem. From that day on, I had a different point of view towards cell phones: Phones really take us away fromthe rest of the world, but we do have to make some time to spend with our family too and don't get stuck withour phones all day.
35.【答案】(除标注外,每空2分)(1)14:13(2)Co2 的价电子排布式为3d,Fe2的价电子排布式为3d,Fe2 易失去1个电子变为3d3的稳定结构(3)①sp2、sp3O>Cl>C>H②∏5(4)bd(5)56×6 14×2(3分)Ax2xy×6xN【必备知识】原子核外电子排布、电离能、电负性、杂化方式、晶体结构、晶胞计算【解题思路】(1)铁元素的原子序数为26,亚铁离子和铁离子的最外层电子排布式为3323p3d和33p°3d3(注意:M层包括s、pd3个能级),则最外层电子数之比为14:13。(2)Co为27号元素,Co2的价电子排布式为3d,Fe2的价电子排布式为3d°,Fe2失去1个电子形成3d,3d为半充满的稳定结构,则与Co2相比,Fe2 易失去1个电子形成Fe,导致钴元素的第三电离能大于铁元素的第三电离能。(3)①环戊二烯分子中形成碳碳双键的碳原子的杂化方式为sp2,形成饱和碳原子的杂化方式为sp3;非金属性越强,电负性越大,则题给反应中所有非金属元素的电负性由大到小的顺序为0>Cl>C>H②环戊二烯负离子(),所有碳原子都采取sP2杂化,e旁的C原子上p轨道有一对孤对电子,其参与构成大τ键,则环戊二烯负离子中的大丌键由5个碳原子、6个电子构成,该大键可表示为∏5。(4)由可知,-Fe属于体心立方堆积,室间利用率为68%,故a错误;由可知,y属于画心这方最密堆积配位数为12,故b正确;金属延展时,金属键不变,金属原子排列方式不变,即晶胞结构不变,所以a-Fe延展时,不可能转变为y-Fe,故e错误;金属Fe中含有自由电子,在通电时自由电子作定向移动形成电流而导电,故d正确。(5)由晶胞结构可知,晶胞含有12× 2× 3=6个Fe原子,含有2个N原子,六棱柱的底面由6个正三角形构成,正三角形的高为xcm,每个正三角形的面积为42cm,品晶胞的体积为6×4xycm2,则晶胞的密度为56×6 14×2g·cm。4xxy×6xNA
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