第二节【语篇类型】记叙文【主题语境】人与自我——生活态度【文章大意】作者被诊断得了乳腺癌,手术后为了避免复发,需要进行化疗,但因为特殊的形势,家人不能在医院陪护她。作者一度情绪低沉,但是慢慢地作者转变了态度。在医疗人员的关怀下,作者战胜了疾病,也收获了真正的友谊和自信。【写作指导】 Paragraph1的开头是"我决定做出更多积极的改变",因此本段续写要体现出作者在化疗过程中行为和态度的积极Paragraph2的开头是"此外,我从负贲化疗的团队中获得了支持",因此接下来的内容应该以描述医疗工作人员对作者的支持、作者和他们的相处以及作者的感受为主,可以作者对所有支持和帮助过自己的人表达感谢来作为文章的结尾。One possible versionaragraph II decided to make more positive changehair lossdoesn't mean I'm not pretty anymore. Failing to visit the hairdresser's, Idecided to shave my head. With teary eyes, I whispered, "Goodbye,mhair. Goodbye cancer. When I looked in the mirror I didnt see thehair that was missing, but the confidence on my face. And whergained my strength, instead of worrying about work arrangements, I reador listened to podcasts, which became rare relaxing time for meParagraph 2What's more, I found support in my chemo team. Initially nothingrightened me as much as the prospect of chemo especially withoutcompany of a loved one. But kindness and sensitivity of the chemo crewwas a comfort. I'd ask the nurses what they did in their off-time. Mteam would clap as I'd tick off another completed session, I treasure thememory of my recently completed final session: we danced as I"rangthe bell "-a graduation ceremony marking the end of a patientscourse of cherno
20解:(1)f(x)=√3cos2x 2sin3 cos 2x-2cos rsin x =3 cos 2r- sin 2x(3分)所以f(x)的最小正周期T=2=兀(4分)当2kx 兀≤2x ≤2kx 2x,k∈Z,即kx十≤x≤k丌 一,k∈Z时,函数∫(x)单调递增,所以函数f(x)的单调递增区间为kx 17,x11m121k∈Z(6分)(2)因为f(A)=-√3,所以f(A)=2cos2A √3即(2 )√3因为A∈(0.5),所以2A x∈(x,26因为A∈(o.2).所以2A 5∈/,x5所以2A 一=一,得A=(8分)设BC边上的高为h,则-ahbcsin a即h=~bc.由余弦定理得9=b2 c2-bc,又因为b2 c2≥2bc,所以b≤9(当且仅当b=c时取等号所以63√3所以BC边上的高的最大值为(12分)
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