33.【物理选修33】(15分)(1)(5分)ACE。(选对1个得2分,选对2个得4分,选对3个得5分。没选错1个扣3分,最低得分为0分)(2)(10分)解(i)设气体柱横截面积为s,对封闭气体柱管口向下时,P=0gh50cmHg,=s,h=280K管口向上时,P=m pg100cmHg,=sh,h2=280K分分由玻意耳定律P=P(2分)解得6=35 cm(1分))设玻璃管中气体的温度升高到/时,水银恰好不溢出,对封闭气体柱3=P2=100cmHg,的=(6-),/3=?(2分)由盖吕萨克定律上=4(2分)解得/3=600K(1分)
书面表达One possible version:NOTICEA sports meeting will be held in the playground of our school from next Thursday to FridayAs you know, the pressure of study is very heavy now, especially for those senior 3. So the purpose of the sports meeting is to letevery student get relaxed, as a result of which we students can live happily and heal thilyEveryone is welcome to take part in it. Those who perform excellently at the sports meeting will get prizes. But don' t take theresults so serously because taking part is more important than the result. Good luck to everyone!
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